The simple workout to arrive at the initial values for sha-256 The first 32 bit of the fractional part of the sqroot (first 8 prime number 2-19) Alright what does it say Sqrroot(prime)- Let’s say the first prime is 2 Sqroot(2) = 1.414213562373095 Convert to hexadecimal- Since we are worried about the fractional part alone Converting the fractional part would be easy Fractional part- 0.414213562373095 Multiply the fractional part with 16 to arrive at hex 0.414213562373095*16= 6.62741699796952 0.62741699796952*16= 10.03867196751232 0.03867196751232*16=0.61875148019712 0.61875148019712*16=9.90002368315392 0.90002368315392*16=14.40037893046272 0.40037893046272*16=6.40606288740352 0.40606288740352*16=6.49700619845632 0.49700619845632*16=7.95209917530112 Resulting hexadecimal would be 6a09e667 which is h0 := 0x6a09e667 Iam going to stop at the 8th iteration , why is that ? Since we are interested in 32 bit (8*4=32) Alright to make it clear Convert hexadecimal- binary arriving at 32 bits
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